Why the derivative of sin(ax) is a·cos(ax)
With u = ax and du/dx = a, the chain rule gives d/dx[sin(u)] = cos(u) · a = a·cos(ax).
Examples: d/dx[sin(2x)] = 2·cos(2x), d/dx[sin(x/3)] = ⅓·cos(x/3).
Compute the derivative of sin(ax) at a specific x value (x in radians).
Adjust values in real-time and observe mathematical cause-and-effect
Bounded Oscillatory Function: Sine and cosine oscillate smoothly between -1 and +1 with period 360° (2π rad).
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Bounded Oscillatory Function: Sine and cosine oscillate smoothly between -1 and +1 with period 360° (2π rad).
Ratio of side lengths → Dimensionless Scalar [-1, +1]
Audio sound wave synthesis, AC alternating current electrical waveforms, robotic arm joint kinematics, and astronomical navigation.
With u = ax and du/dx = a, the chain rule gives d/dx[sin(u)] = cos(u) · a = a·cos(ax).
Examples: d/dx[sin(2x)] = 2·cos(2x), d/dx[sin(x/3)] = ⅓·cos(x/3).
Given:
Answer: 1
d/dx[sin(ax)] = a·cos(ax). Compute the derivative of sin(ax) at a specific x value (x in radians).
Enter Coefficient (a), Value of x (radians) (x) into the calculator. It applies d/dx[sin(ax)] = a·cos(ax) and shows every step of the working.
a·cos(ax), by the chain rule.
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